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SQL Puzzle | The Weird String Puzzle
In this puzzle you have to read a string value for example – 11Ab220111bbb5555ccc4444.
We have to get data like below-
If any character is repeating after the first occurance we have to print that number.
Example
1 -> for this we need to print 111 since 1 is repeating.
b -> for tihs we need to print bbb since b is repeating.
for other just print the character as they are not repeating. We do not have to print the duplicate characters.
Sample Input
WeirdValue |
---|
11Ab220111bbb5555ccc4444 |
Expected Output
Number | PrintAs |
---|---|
0 | 0 |
1 | 1, 1, 1 |
2 | 2 |
4 | 4 |
5 | 5 |
A | A |
b | b, b, b |
c | c |
Script
Use below script to create table and insert sample data into it.
-- DECLARE @WeirdValue NVARCHAR(255) = N'11Ab220111bbb5555ccc4444'; SELECT @WeirdValue WeirdValue -- |
Rules/Restrictions
The solution should be should use “SELECT” statement or “CTE”.
Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com
Solution – 1
-- DECLARE @WeirdValue NVARCHAR(255) = N'11Ab220111bbb5555ccc4444'; ;WITH SingleDigits(Number) AS ( SELECT Number FROM (VALUES (1), (2), (3), (4), (5), (6), (7), (8), (9), (0)) AS X(Number) ) ,Series AS ( SELECT (d1.Number+1) + (10*d2.Number) + (100*d3.Number) + (1000*d4.Number) Number from SingleDigits as d1, SingleDigits as d2, SingleDigits as d3, SingleDigits as d4 ) ,CTE AS ( SELECT *, SUBSTRING(@WeirdValue,Number,1) Nums FROM Series WHERE Number <= LEN(@WeirdValue) ) ,CTE1 AS ( SELECT * , CASE WHEN Nums = lag(Nums) OVER(ORDER BY Number) THEN 0 ELSE 1 END cols FROM CTE ) ,CTE2 AS ( SELECT * , SUM(cols) OVER (PARTITION BY Nums ORDER BY Number) grouper FROM CTE1 ) ,CTE3 AS ( SELECT nums FROM CTE2 c WHERE grouper = 2 UNION ALL SELECT DISTINCT nums FROM CTE2 r WHERE grouper = 1 AND NOT EXISTS ( SELECT NULL FROM CTE2 c1 WHERE r.Nums = c1.Nums AND grouper = 2 ) ) ,CTE4 AS ( SELECT DISTINCT nums nums1 , STUFF (( SELECT ', ' + CAST(nums AS VARCHAR) FROM CTE3 a WHERE ( a.nums = b.nums ) FOR XML PATH('') ) ,1,2,'') AS nums FROM CTE3 b ) SELECT nums1 Number , nums PrintAs FROM CTE4 -- |
Output
-- /*------------------------ DECLARE @WeirdValue NVARCHAR(255) = N'11Ab220111bbb5555ccc4444'; ;WITH SingleDigits(Number) AS ( SELECT Number FROM (VALUES (1), (2), (3), (4), (5), (6), (7), (8), (9), (0)) AS X(Number) ) ,Series AS ( SELECT (d1.Number+1) + (10*d2.Number) + (100*d3.Number) + (1000*d4.Number) Number from SingleDigits as d1, SingleDigits as d2, SingleDigits as d3, SingleDigits as d4 ) ,CTE AS ( SELECT *, SUBSTRING(@WeirdValue,Number,1) Nums FROM Series WHERE Number <= LEN(@WeirdValue) ) ,CTE1 AS ( SELECT * , CASE WHEN Nums = lag(Nums) OVER(ORDER BY Number) THEN 0 ELSE 1 END cols FROM CTE ) ,CTE2 AS ( SELECT * , SUM(cols) OVER (PARTITION BY Nums ORDER BY Number) grouper FROM CTE1 ) ,CTE3 AS ( SELECT nums FROM CTE2 c WHERE grouper = 2 UNION ALL SELECT DISTINCT nums FROM CTE2 r WHERE grouper = 1 AND NOT EXISTS ( SELECT NULL FROM CTE2 c1 WHERE r.Nums = c1.Nums AND grouper = 2 ) ) ,CTE4 AS ( SELECT DISTINCT nums nums1 , STUFF (( SELECT ', ' + CAST(nums AS VARCHAR) FROM CTE3 a WHERE ( a.nums = b.nums ) FOR XML PATH('') ) ,1,2,'') AS nums FROM CTE3 b ) SELECT nums1 Number , nums PrintAs FROM CTE4 ------------------------*/ Number PrintAs ------ ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- 0 0 1 1, 1, 1 2 2 4 4 5 5 A A b b, b, b c c (8 row(s) affected) --
Add a comment if you have any other solution in mind. I would love to learn it. We all need to learn.
Enjoy !!! Keep Learning
Pawan Khowal
Http://MSBISkills.com
Thank you for coming up with such wonderful puzzles, Pawan. I thoroughly enjoying solving and learning them.
in this particular puzzle, however the “expected output” is incorrect based on your explanation because
1 should be 1,1,1,1 (it is repeated 4 times after first time)
2 is fine
4 should be 4,4,4 (it is repeated 3 times after first time) etc;
Or may be my understanding of the question is incorrect. However based on my understanding, here is my solution to it
——————————————————————————————————————————————————————–
DECLARE @WeirdValue NVARCHAR(255) = N’11Ab220111bbb5555ccc4444′;
SELECT @WeirdValue WeirdValue
;With T as
(
Select i=1,WeirdValue=@WeirdValue,c=substring(@WeirdValue,1,1)
Union All
Select i=i+1,WeirdValue,c=substring(@WeirdValue,i,1) From T
Where i<=len(@WeirdValue)
)
,T2 As
(
Select c,CASE WHEN datalength(replicate(c,(Len(@WeirdValue)-Len(Replace(@WeirdValue,c,'')))-1))=0 THEN '0'
ELSE stuff(replicate(','+c,(Len(@WeirdValue)-Len(Replace(@WeirdValue,c,'')))-1),1,1,'') END col From T
Group by c,stuff(replicate(','+c,(Len(@WeirdValue)-Len(Replace(@WeirdValue,c,'')))-1),1,1,'')
)Select * From T2
LikeLiked by 1 person
Thank you very much.
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