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Improving my SQL BI Skills

Improving my SQL BI Skills

Tag Archives: T-SQL Query | [ Replace 6 or more Consecutive Digits with x from a string Puzzle ]

SQL Puzzle | Split String Puzzle – II (Linked In)

06 Tuesday Oct 2015

Posted by Pawan Kumar Khowal in T SQL Puzzles, Tricky SQL Queries

≈ 2 Comments

Tags

Complex SQL Challenges, complex sql statement(puzzle), Complex TSQL Challenge, Divide rows into two columns, find records not ending with s, find records not ending with s puzzle, Interesting Interview Questions, Interview Puzzles in SQL Server, Interview Qs.SQL SERVER Questions, Interview questions on Joins, Interview Questions on SQL, Interview SQL Puzzles, InterviewQuestions, InterviewQuestions for SQL, Joins, Joins Interview questions, Joins Puzzle, Khowal, last non null puzzle, Learn complex SQL, Learn SQL, Learn T-SQL, Objective Puzzle, Pawan, Pawan Khowal, Pawan Kumar, Pawan Kumar Khowal, PL/SQL Challenges, Prev Value puzzle, Previous value puzzle, Puzzle SQL, puzzle sql developer, Puzzle SQl Server, Puzzles, PUzzles in SQL SERVER, Queries for SQL Interview, Records not ending with a character Puzzle, Records not ending with s Puzzle, SELECT Puzzle, SQL, SQL 2012, SQL 2014, SQL 2014 Interview Questions, SQL Challenge, SQL Challenges, SQL Interview Questions, SQL Joins, SQL pl/sql puzzles, SQL puzzle, SQL Puzzle | Split String Puzzle - II (Linked In), SQL Puzzles, SQL Queries, SQL Quiz, SQL Server Database, SQL server filter index with LIKE and RIGHT function?, SQL Server Interview Puzzle, SQL SERVER Interview questions, SQL Server Puzzle, SQL SERVER Puzzles, SQL Skills, SQL Sudoku, SQL Top clause, SQL Trikcy question, sql/database interview for puzzle sql developer, SQLSERVER, T SQL Puzzles, T-SQL Challenge, T-SQL Puzzle, T-SQL Query | [ Replace 6 Consecutive Digits with x from a string Puzzle ], T-SQL Query | [ Replace 6 or more Consecutive Digits with x from a string Puzzle ], T-SQL Query | [ The Complex Week Puzzle ], T-SQL Tricky Puzzles, The Biggest Gap Puzzle, The Gap Puzzle, The Gap Puzzle Puzzle, The Tree Puzzle, TOP Clause, Tough SQL Challenges, Tough SQL Puzzles, Tricky Questions, TSQL, TSQL Challenge, TSQL Challenges, TSQL Interview questions, TSQL Puzzle, TSQL Puzzles, TSQL Queries, Week puzzle, What You Can (and Can't) Do With Filtered Indexes


SQL Puzzle | Split String Puzzle – II (Linked In)

Puzzle Statement

This puzzle was asked in social media ( Linked In ), In this puzzle you have to split a string and insert in the same column. Basically here the number will be increased based on the id column.

SQL Puzzle - Linked In

SQL Puzzle – Linked In

Check out the input and output required for this puzzle is-

Sample Input

1 a,b,c
2 c,d
3 e,f
4 x

Expected output

ID SplittedString
1 a
1 b
1 c
2 c
2 d
3 e
3 f
4 x

Rules/Restrictions

The solution should be should use “SELECT” statement or “CTE”.
Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com
Script

Use the below script to generate the source table and fill them up with the sample data.

UPDATE – 6-Oct-2015 – Solution #1

--

SELECT ID, SplittedString FROM
(
	SELECT  ID, CAST('<A>'+ REPLACE(Value,',','</A><A>')+ '</A>' AS XML) Xmlcol FROM SplitString2
) s
CROSS apply
(
	SELECT ProjectData.D.value('.', 'VARCHAR(5)') as SplittedString
	FROM s.xmlcol.nodes('A') as ProjectData(D)
)a

--

Add a comment if you have any other solution in mind. We all need to learn. Enjoy !!!

Keep Learning

Pawan Khowal 

Http://MSBISkills.com

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SQL Server Question – Why does SUM of an empty table returns NULL & Not 0 ?

05 Monday Oct 2015

Posted by Pawan Kumar Khowal in T SQL Puzzles, Tricky SQL Queries

≈ Leave a comment

Tags

Complex SQL Challenges, complex sql statement(puzzle), Complex TSQL Challenge, Divide rows into two columns, find records not ending with s, find records not ending with s puzzle, Interesting Interview Questions, Interview Puzzles in SQL Server, Interview Qs.SQL SERVER Questions, Interview questions on Joins, Interview Questions on SQL, Interview SQL Puzzles, InterviewQuestions, InterviewQuestions for SQL, Joins, Joins Interview questions, Joins Puzzle, Khowal, last non null puzzle, Learn complex SQL, Learn SQL, Learn T-SQL, Objective Puzzle, Pawan, Pawan Khowal, Pawan Kumar, Pawan Kumar Khowal, PL/SQL Challenges, Prev Value puzzle, Previous value puzzle, Puzzle SQL, puzzle sql developer, Puzzle SQl Server, Puzzles, PUzzles in SQL SERVER, Queries for SQL Interview, Records not ending with a character Puzzle, Records not ending with s Puzzle, SELECT Puzzle, SQL, SQL 2012, SQL 2014, SQL 2014 Interview Questions, SQL Challenge, SQL Challenges, SQL Interview Questions, SQL Joins, SQL pl/sql puzzles, SQL puzzle, SQL Puzzles, SQL Queries, SQL Quiz, SQL Server Database, SQL server filter index with LIKE and RIGHT function?, SQL Server Interview Puzzle, SQL SERVER Interview questions, SQL Server Puzzle, SQL SERVER Puzzles, SQL Skills, SQL Sudoku, SQL Top clause, SQL Trikcy question, sql/database interview for puzzle sql developer, SQLSERVER, T SQL Puzzles, T-SQL Challenge, T-SQL Puzzle, T-SQL Query | [ Replace 6 Consecutive Digits with x from a string Puzzle ], T-SQL Query | [ Replace 6 or more Consecutive Digits with x from a string Puzzle ], T-SQL Query | [ The Complex Week Puzzle ], T-SQL Tricky Puzzles, The Biggest Gap Puzzle, The Gap Puzzle, The Gap Puzzle Puzzle, The Tree Puzzle, TOP Clause, Tough SQL Challenges, Tough SQL Puzzles, Tricky Questions, TSQL, TSQL Challenge, TSQL Challenges, TSQL Interview questions, TSQL Puzzle, TSQL Puzzles, TSQL Queries, Week puzzle, What You Can (and Can't) Do With Filtered Indexes


Friends, I have a quick question for you. Why does SUM of an empty table returns NULL & Not 0 ?  Let me just create some sample examples for you.

Example 1

--

CREATE TABLE testSUMNulls
(
	ID TINYINT
)
GO

INSERT INTO testSUMNulls (ID) VALUES (NULL),(NULL),(NULL),(NULL)

SELECT SUM(ID) FROM testSUMNulls

--

Example 2

--

CREATE TABLE testSumEmptyTable
(
	ID TINYINT
)
GO

SELECT SUM(ID) Sums FROM testSumEmptyTable

--

Example 3

--

CREATE TABLE testSumTable
(
	ID TINYINT
)
GO

INSERT INTO testSumTable(ID)
VALUES
(10),(20),(30),(40)

SELECT SUM(ID) Sums FROM testSumTable
WHERE ID = 1

--

Now in all the cases we will get NULL as the sum output. Now in all the cases we will get NULL as the sum output. As far as I know SQL internally works with Bags(https://msbiskills.com/2015/09/15/sql-server-what-are-bags-sets/) not sets. Now if our bag doesn’t have anything why we are getting NULL and not 0. Now the question is why it so ? 

Please add your answers in the comments section. Enjoy !! We all need to learn.

MSBISKILLS.COM

Pawan Kumar Khowal

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T-SQL Query | [ Replace 6 or more Consecutive Digits with x from a string Puzzle ]

05 Monday Oct 2015

Posted by Pawan Kumar Khowal in T SQL Puzzles, Tricky SQL Queries

≈ 6 Comments

Tags

Complex SQL Challenges, complex sql statement(puzzle), Complex TSQL Challenge, Divide rows into two columns, find records not ending with s, find records not ending with s puzzle, Interesting Interview Questions, Interview Puzzles in SQL Server, Interview Qs.SQL SERVER Questions, Interview questions on Joins, Interview Questions on SQL, Interview SQL Puzzles, InterviewQuestions, InterviewQuestions for SQL, Joins, Joins Interview questions, Joins Puzzle, Khowal, last non null puzzle, Learn complex SQL, Learn SQL, Learn T-SQL, Objective Puzzle, Pawan, Pawan Khowal, Pawan Kumar, Pawan Kumar Khowal, PL/SQL Challenges, Prev Value puzzle, Previous value puzzle, Puzzle SQL, puzzle sql developer, Puzzle SQl Server, Puzzles, PUzzles in SQL SERVER, Queries for SQL Interview, Records not ending with a character Puzzle, Records not ending with s Puzzle, SELECT Puzzle, SQL, SQL 2012, SQL 2014, SQL 2014 Interview Questions, SQL Challenge, SQL Challenges, SQL Interview Questions, SQL Joins, SQL pl/sql puzzles, SQL puzzle, SQL Puzzles, SQL Queries, SQL Quiz, SQL Server Database, SQL server filter index with LIKE and RIGHT function?, SQL Server Interview Puzzle, SQL SERVER Interview questions, SQL Server Puzzle, SQL SERVER Puzzles, SQL Skills, SQL Sudoku, SQL Top clause, SQL Trikcy question, sql/database interview for puzzle sql developer, SQLSERVER, T SQL Puzzles, T-SQL Challenge, T-SQL Puzzle, T-SQL Query | [ Replace 6 Consecutive Digits with x from a string Puzzle ], T-SQL Query | [ Replace 6 or more Consecutive Digits with x from a string Puzzle ], T-SQL Query | [ The Complex Week Puzzle ], T-SQL Tricky Puzzles, The Biggest Gap Puzzle, The Gap Puzzle, The Gap Puzzle Puzzle, The Tree Puzzle, TOP Clause, Tough SQL Challenges, Tough SQL Puzzles, Tricky Questions, TSQL, TSQL Challenge, TSQL Challenges, TSQL Interview questions, TSQL Puzzle, TSQL Puzzles, TSQL Queries, Week puzzle, What You Can (and Can't) Do With Filtered Indexes


T-SQL Query | [ Replace 6 or more Consecutive Digits with x from a string Puzzle ]

Yesterday I was going through one of the puzzle asked in SQL Server Central website. The question is not simple 🙂 ; Here you have to replace all integers with continuous 6 or more occurrences with ‘X’. Less than 6 occurrences of integers should not be replaced. All other characters should not be touched. Let’s first go through the sample input and expected output below-

Pictorial presentation of the puzzle.(Pic taken from SQL Server Central website)

SQL Server Central Puzzle

SQL Server Central Puzzle

Sample Input

InputString
1234ABC123456XYZ1234567890ADS
1234
123456
123456A!@#$%
9876542345672a345673456734567
9876542345672345673456734567
a1AAAAAAAAAAAAAAAAAAAAAAA12345
AAAAAA

Expected Output

InputString ReplacedString
1234ABC123456XYZ1234567890ADS 1234ABCXXXXXXXYZXXXXXXXXXXADS
1234 1234
123456 XXXXXX
123456A!@#$% XXXXXXA!@#$%
9876542345672a345673456734567 XXXXXXXXXXXXXaXXXXXXXXXXXXXXX
9876542345672345673456734567 XXXXXXXXXXXXXXXXXXXXXXXXXXXX
a1AAAAAAAAAAAAAAAAAAAAAAA12345 a1AAAAAAAAAAAAAAAAAAAAAAA12345
AAAAAA AAAAAA

Rules/Restrictions

Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com

Script

Use the below script to generate the source table and fill them up with the sample data.

--

--Create table and insert some data

CREATE TABLE DigitsToReplace 
(
	Chrs VARCHAR(1000)	
)
GO 

INSERT INTO DigitsToReplace VALUES ('1234ABC123456XYZ1234567890ADS')
INSERT INTO DigitsToReplace VALUES ('1234')
INSERT INTO DigitsToReplace VALUES ('123456')
INSERT INTO DigitsToReplace VALUES ('123456A!@#$%')
INSERT INTO DigitsToReplace VALUES ('')
INSERT INTO DigitsToReplace VALUES (' ')
INSERT INTO DigitsToReplace VALUES ('9876542345672a345673456734567')
INSERT INTO DigitsToReplace VALUES ('9876542345672345673456734567')
INSERT INTO DigitsToReplace VALUES ('a1AAAAAAAAAAAAAAAAAAAAAAA12345')
INSERT INTO DigitsToReplace VALUES ('AAAAAA')

--

Update Oct 5 | Solutions # – Pawan Kumar Khowal

--

--Table Valued function

CREATE FUNCTION [dbo].[Replace6ContinousDigits] 
(
	@InputString VARCHAR(1000)
)
RETURNS @results TABLE
(
	final VARCHAR(1000)
)
AS 
BEGIN
	
	DECLARE @Sttrs AS VARCHAR(1000) = @InputString
	DECLARE @totals AS INT = 0
	DECLARE @Counter AS INT = 1

	SET @totals = DATALENGTH(@Sttrs)
	
	DECLARE @Chrs TABLE (rnk TinyInt , Chars Char(1) , Digit TinyInt)

	WHILE (@Counter <= @totals) 
        BEGIN 
            INSERT INTO @Chrs VALUES 
            ( 
               @Counter 
               ,SUBSTRING(@Sttrs,@Counter,1) 
               ,CASE WHEN SUBSTRING(@Sttrs,@Counter,1) LIKE '[0-9]' THEN 1 ELSE  
               @Counter                 
            END 
            ) 
        SET @Counter = @Counter + 1 
        END 

;WITH CTE AS 
( 
    SELECT *, CASE WHEN Digit = lag(Digit) OVER(ORDER BY rnk) THEN 0 ELSE 1 END cols  FROM @Chrs c2 
) 
,CTE1 AS 
( 
   SELECT * , SUM(cols) OVER (ORDER BY rnk) grouper FROM CTE 
) 
,CTE2 AS 
( 
   SELECT *, COUNT(*) OVER (PARTITION BY grouper) ConsecutiveDigits FROM CTE1 
) 
,CTE3 AS 
( 
   SELECT chars, ConsecutiveDigits , ROW_NUMBER() OVER (PARTITION BY ConsecutiveDigits ORDER BY (SELECT NULL)) nkr FROM CTE2 c WHERE c.ConsecutiveDigits &amp;gt; 5
)
UPDATE c SET c.Chars = 'X'
FROM CTE3 c

DECLARE @final AS VARCHAR(1000) = ''
SELECT @final = @final + Chars FROM @Chrs

INSERT @results (final) SELECT @final

RETURN;
END


---Usage

SELECT Chrs InputString, final ReplacedString FROM DigitsToReplace
CROSS APPLY
(
	SELECT final FROM [dbo].[Replace6ContinousDigits] (Chrs)

) A

--

Thanks Guys ! Add a comment if you have any other solution in mind. We all need to learn. Keep Learning 🙂

Http://MSBISkills.com

Pawan Kumar Khowal

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