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SQL PUZZLE | How to Select/Generate the numbers between two numbers? | SQL Interview Question
In this puzzle you have to select the numbers between two numbers. Please check the sample input and expected output for more details
Sample Input
Id | St | Et |
---|---|---|
1 | 2 | 7 |
2 | 10 | 15 |
3 | 16 | 18 |
Expected Output
Id | St | Et | Number |
---|---|---|---|
1 | 2 | 7 | 2 |
1 | 2 | 7 | 3 |
1 | 2 | 7 | 4 |
1 | 2 | 7 | 5 |
1 | 2 | 7 | 6 |
1 | 2 | 7 | 7 |
2 | 10 | 15 | 10 |
2 | 10 | 15 | 11 |
2 | 10 | 15 | 12 |
2 | 10 | 15 | 13 |
2 | 10 | 15 | 14 |
2 | 10 | 15 | 15 |
3 | 16 | 18 | 16 |
3 | 16 | 18 | 17 |
3 | 16 | 18 | 18 |
Script – DDL and INSERT Script
-- CREATE TABLE Nums ( Id INT ,St INT ,Et INT ) GO INSERT INTO Nums VALUES (1,2,7), (2,10,15), (3,16,18) GO SELECT * FROM Nums GO -- |
Rules/Restrictions
The solution should be should use “SELECT” statement or “CTE”.
SOLUTION 1
-- ;WITH SingleDigits(Number) AS ( SELECT Number FROM (VALUES (1), (2), (3), (4), (5), (6), (7), (8), (9), (0)) AS X(Number) ) ,Series AS ( SELECT (d1.Number+1) + (10*d2.Number) + (100*d3.Number) + (1000*d4.Number) Number from SingleDigits as d1, SingleDigits as d2, SingleDigits as d3, SingleDigits as d4 ) SELECT * FROM Nums N INNER JOIN Series s ON s.Number >= N.St AND s.Number <= N.Et ORDER BY Id,Number -- |
OUTPUT – 1
-- Id St Et Number ----------- ----------- ----------- ----------- 1 2 7 2 1 2 7 3 1 2 7 4 1 2 7 5 1 2 7 6 1 2 7 7 2 10 15 10 2 10 15 11 2 10 15 12 2 10 15 13 2 10 15 14 2 10 15 15 3 16 18 16 3 16 18 17 3 16 18 18 (15 rows affected) -- |
SOLUTION 2
-- SELECT DISTINCT N.* , S.number FROM master..spt_values s INNER JOIN Nums N ON s.number >= N.St AND s.Number <= N.Et WHERE s.number > 0 ORDER BY Id,s.Number -- |
OUTPUT
-- Id St Et number ----------- ----------- ----------- ----------- 1 2 7 2 1 2 7 3 1 2 7 4 1 2 7 5 1 2 7 6 1 2 7 7 2 10 15 10 2 10 15 11 2 10 15 12 2 10 15 13 2 10 15 14 2 10 15 15 3 16 18 16 3 16 18 17 3 16 18 18 (15 rows affected) -- |
Please add a comment if you have any other or better solution in mind. I would love to learn it. We all need to learn. Thanks in advance.
Pawan Khowal
Pawan is a SQL Server Developer. If you need any help in writing code/puzzle or training please email at – pawankkmr”AT”gmail.com. Meanwhile please go throgh the top pages from his blog.
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;with cte
as
(
select ID,st,Et,st as number from #Nums a
union all
select id,st,Et,number+1
from cte
where number<et
)
select * from cte
order by Id
LikeLiked by 1 person
Cool…Recursive Method 🙂 Great going.
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This is just a slightly different version of the CTE above (i added a prior CTE to provide rows )
with cteA as (
select id,
st,
et
FROM Nums
),
cteB as (
select id,
st,
et,
number = st
from cteA
union all
select id,
st,
et,
number +1 as number
from cteB
where number < et
)
select *
from cteB
order by id,number
LikeLiked by 1 person
Hi There,
A spot on observation on what probably is “the” underlying details of the SQL Interview Question.Too many people don’t even think about wherever there will be actual demand and more importantly what happens if this demand comes later (or maybe a lot later) than they expect
How can I amend this select to make a sum & group by a single line
SELECT article_ref, status, total_amount
FROM order_tbl
GROUP BY article_ref, status, total_amount
ORDER BY article_ref, status, total_amount;
tbl_order
article_ref status total_amount
123456 Ordered 100
123456 Ordered 10
123456 Ordered 80
123456 Pending 50
123456 Pending 23
123456 Pending 50
123456 Delivered 50
123456 Delivered 75
And want the output to be
123456 Ordered 190
123456 Pending 123
123456 Delivered 125
It was cool to see your article pop up in my google search for the process yesterday. Great Guide.
Keep up the good work!
Grazie,
Preethi
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