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Check for leap year, TSQL Challenge, TSQL Challenges, TSQL Interview questions, TSQL Puzzle, TSQL Puzzles, TSQL Queries, User-Defined Functions - Determine Leap Year
SQL SERVER | Find whether the year is a Leap year or not? | SQL Interview Question
Ref – https://www.mathsisfun.com/leap-years.html
There are two types of Years – Leap year and Non Leap year. Lets first understand what are they-
Leap Year
- A normal year has 365 days.
- A Leap Year has 366 days (the extra day is the 29th of February).
How to know if a year will be a Leap Year:
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Leap Years are any year that can be evenly divided by 4 (such as 2012, 2016, etc) | ||
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except if it can can be evenly divided by 100, then it isn’t (such as 2100, 2200, etc) | ||
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except if it can be evenly divided by 400, then it is (such as 2000, 2400) |
–Find Whether a Year is a Leap Year or NOT?
–SOLUTION 1
-- --Example1 DECLARE @Yr INT = 2018 SELECT @Yr [Year] , IIF ((@Yr % 4 = 0 AND @Yr % 100 != 0) OR @Yr % 400 = 0, 'Leap Year','Not a Leap Year') [IsLeapYear] GO OUTPUT Year IsLeapYear ----------- --------------- 2018 Not a Leap Year (1 row affected) -- |
-- --Example2 DECLARE @Yr INT = 2012 SELECT @Yr [Year] , IIF ((@Yr % 4 = 0 AND @Yr % 100 != 0) OR @Yr % 400 = 0, 'Leap Year','Not a Leap Year') [IsLeapYear] GO Year IsLeapYear ----------- --------------- 2012 Leap Year (1 row affected) -- |
–SOLUTION 2
-- --Example1 DECLARE @Yr INT = 2018 SELECT @Yr [Year] , IIF ( DAY(EOMONTH(DATEFROMPARTS(@yr,2,1))) = 29 , 'Leap Year','Not a Leap Year') [IsLeapYear] GO Year IsLeapYear ----------- --------------- 2018 Not a Leap Year (1 row affected) -- |
-- --Example2 DECLARE @Yr INT = 2012 SELECT @Yr [Year] , IIF ( DAY(EOMONTH(DATEFROMPARTS(@yr,2,1))) = 29 , 'Leap Year','Not a Leap Year') [IsLeapYear] GO Year IsLeapYear ----------- --------------- 2012 Leap Year (1 row affected) -- |
–Find Whether a Date is a Leap Year or NOT?
–SOLUTION 1
-- --Example1 DECLARE @Yr INT = YEAR('2012/01/01') SELECT @Yr [Year] , IIF ((@Yr % 4 = 0 AND @Yr % 100 != 0) OR @Yr % 400 = 0, 'Leap Year','Not a Leap Year') [IsLeapYear] GO OUTPUT Year IsLeapYear ----------- --------------- 2012 Leap Year (1 row affected) -- |
-- --Example2 DECLARE @Yr INT = YEAR('2018/01/01') SELECT @Yr [Year] , IIF ((@Yr % 4 = 0 AND @Yr % 100 != 0) OR @Yr % 400 = 0, 'Leap Year','Not a Leap Year') [IsLeapYear] GO OUTPUT Year IsLeapYear ----------- --------------- 2018 Not a Leap Year (1 row affected) -- |
–SOLUTION 2
-- --Example1 DECLARE @Yr INT = YEAR('2018/01/01') SELECT @Yr [Year] , IIF ( DAY(EOMONTH(DATEFROMPARTS(@yr,2,1))) = 29 , 'Leap Year','Not a Leap Year') [IsLeapYear] GO OUTPUT Year IsLeapYear ----------- --------------- 2018 Not a Leap Year (1 row affected) -- |
-- --Example2 DECLARE @Yr INT = YEAR('2012/01/01') SELECT @Yr [Year], IIF ( DAY(EOMONTH(DATEFROMPARTS(@yr,2,1))) = 29 , 'Leap Year','Not a Leap Year') [IsLeapYear] GO --OUTPUT Year IsLeapYear ----------- --------------- 2012 Leap Year (1 row affected) -- |
SOLUTION 3
-- --Example1 DECLARE @Yr INT = YEAR('2012/01/01') SELECT @Yr [Year] , IIF ( TRY_CAST ( CONCAT( @yr , '/2/29') AS DATE) IS NOT NULL , 'Leap Year','Not a Leap Year') [IsLeapYear] GO Year IsLeapYear ----------- --------------- 2012 Leap Year (1 row affected) -- |
-- --Example2 DECLARE @Yr INT = YEAR('2018/01/01') SELECT @Yr [Year], IIF ( TRY_CAST ( CONCAT( @yr , '/2/29') AS DATE) IS NOT NULL , 'Leap Year','Not a Leap Year') [IsLeapYear] GO Year IsLeapYear ----------- --------------- 2018 Not a Leap Year (1 row affected) -- |
Related Puzzle
https://msbiskills.com/2015/04/13/sql-server-find-number-of-days-in-a-year/ |
Note – If you do not have SQL 2012+ then you need to use CASE statement instead of IIF.
Please add a comment if you have any other or better solution in mind. I would love to learn it. We all need to learn. Thanks in advance.
Pawan Khowal
Pawan is a SQL Server Developer. If you need any help in writing code/puzzle or training please email at – pawankkmr”AT”gmail.com. Meanwhile please go throgh the top pages from his blog.
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