SQL Puzzle | READ XML DATA(with Attributes-Single/Multi) using SQL – 2

In this puzzle you have to read XML tags value along with attribute values using T-SQL

Please check the sample input and the expected output.

Sample Input

<Items>	
	<myID ty = "1" />
    <Item>        
        <Id Vals = "a">1</Id>
        <Name>Pawan</Name>        
        <Date>2018/01/01</Date>
    </Item>
    <Item>        
        <Id>2</Id>
        <Name>Avtaar</Name>        
        <Date>2018/01/11</Date>
    </Item>
    <Item>        
        <Id Vals = "c">3</Id>
        <Name>Kishan</Name>         
        <Date>2018/01/20</Date>
    </Item>	
</Items>

Expected Output

Use below script to create table and insert sample data into it.

--

DECLARE @XML AS XML = 
'<Items>	
	<myID ty = "1" />
    <Item>        
        <Id Vals = "a">1</Id>
        <Name>Pawan</Name>        
        <Date>2018/01/01</Date>
    </Item>
    <Item>        
        <Id>2</Id>
        <Name>Avtaar</Name>        
        <Date>2018/01/11</Date>
    </Item>
    <Item>        
        <Id Vals = "c">3</Id>
        <Name>Kishan</Name>         
        <Date>2018/01/20</Date>
    </Item>	
</Items>'

--

Rules/Restrictions

The solution should be should use “SELECT” statement or “CTE”.

Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com

SOLUTION – 1

--


DECLARE @XML AS XML = '
<Items>	
	<myID ty = "1" />
    <Item>        
        <Id Vals = "a">1</Id>
        <Name>Pawan</Name>        
        <Date>2018/01/01</Date>
    </Item>
    <Item>        
        <Id>2</Id>
        <Name>Avtaar</Name>        
        <Date>2018/01/11</Date>
    </Item>
    <Item>        
        <Id Vals = "c">3</Id>
        <Name>Kishan</Name>         
        <Date>2018/01/20</Date>
    </Item>	
</Items>'

DECLARE @m TABLE  (Xmls XML)
INSERT INTO @m SELECT @XML 
;WITH CTE AS
(
    SELECT 
		   p.value(N'(Id)[1]',N'nvarchar(10)') AS [Id]
		  ,p.value(N'(Id/@Vals)[1]',N'nvarchar(10)') AS [Vals]
          ,p.value(N'(Name)[1]',N'nvarchar(20)') AS [Name]
          ,p.value(N'(Date)[1]',N'nvarchar(20)') AS [Dt] 
		  ,p1.value(N'(@ty)[1]',N'nvarchar(20)') AS [ty]      
    FROM @m as x
    OUTER APPLY x.Xmls.nodes(N'/Items/Item') AS u(p)	
	OUTER APPLY x.Xmls.nodes(N'/Items/myID') AS u1(p1)	
)
SELECT *
FROM CTE


--

Output-1

--                            

Id         Vals       Name                 Dt                   ty
---------- ---------- -------------------- -------------------- --------------------
1          a          Pawan                2018/01/01           1
2          NULL       Avtaar               2018/01/11           1
3          c          Kishan               2018/01/20           1

(3 rows affected)


--

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