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SQL Puzzle | Duplicate Data in 5 Minutes Puzzle
In this puzzle we have to find the duplicate data within 5 minutes of each other, the combination used for duplicate data is Individual ID and message text columns Please check the sample input and expected output.
Sample Input
SalesSiteID | MessageID | IndividualId | MessageText | DateAdded |
---|---|---|---|---|
103887 | 1 | 1 | Pawan | 2017-12-14 12:49:22.373 |
103887 | 2 | 1 | Pawan | 2017-12-14 12:49:24.373 |
103887 | 3 | 2 | Sharlee | 2017-12-14 12:49:34.377 |
103887 | 4 | 2 | Sharlee | 2017-12-14 12:50:36.377 |
103887 | 5 | 3 | Ramesh | 2017-12-14 12:50:39.380 |
103887 | 6 | 3 | Ramesh | 2017-12-14 12:50:39.380 |
103887 | 7 | 3 | Ramesh | 2017-12-14 12:51:19.380 |
103887 | 8 | 3 | Ramesh | 2017-12-14 13:01:21.380 |
103887 | 9 | 4 | Avika | 2017-12-14 13:03:23.383 |
103887 | 10 | 5 | Panav | 2017-12-14 13:03:23.387 |
Expected Output
MessageID | MessageID | IndividualID | MessageText | DateAdded | DateAdded |
---|---|---|---|---|---|
1 | 2 | 1 | Pawan | 2017-12-14 12:49:22.373 | 2017-12-14 12:49:24.373 |
3 | 4 | 2 | Sharlee | 2017-12-14 12:49:34.377 | 2017-12-14 12:50:36.377 |
5 | 6 | 3 | Ramesh | 2017-12-14 12:50:39.380 | 2017-12-14 12:50:39.380 |
5 | 7 | 3 | Ramesh | 2017-12-14 12:50:39.380 | 2017-12-14 12:51:19.380 |
6 | 7 | 3 | Ramesh | 2017-12-14 12:50:39.380 | 2017-12-14 12:51:19.380 |
Script
Use below script to create table and insert sample data into it.
-- CREATE TABLE DuplicateFiveMinutes ( SalesSiteID BIGINT ,MessageID BIGINT ,IndividualId BIGINT ,MessageText VARCHAR(200) ,DateAdded DATETIME ) GO INSERT INTO DuplicateFiveMinutes VALUES (103887, 1,1,'Pawan', GETDATE()); WAITFOR DELAY '00:00:02'; INSERT INTO DuplicateFiveMinutes VALUES (103887, 2,1,'Pawan', GETDATE()); WAITFOR DELAY '00:00:10'; INSERT INTO DuplicateFiveMinutes VALUES (103887, 3,2,'Sharlee', GETDATE()); WAITFOR DELAY '00:01:02'; INSERT INTO DuplicateFiveMinutes VALUES (103887, 4,2,'Sharlee', GETDATE()); WAITFOR DELAY '00:00:03'; INSERT INTO DuplicateFiveMinutes VALUES (103887, 5,3,'Ramesh', GETDATE()); INSERT INTO DuplicateFiveMinutes VALUES (103887, 6,3,'Ramesh', GETDATE()); WAITFOR DELAY '00:00:40'; INSERT INTO DuplicateFiveMinutes VALUES (103887, 7,3,'Ramesh', GETDATE()); WAITFOR DELAY '00:10:02'; INSERT INTO DuplicateFiveMinutes VALUES (103887, 8,3,'Ramesh', GETDATE()); WAITFOR DELAY '00:02:02'; INSERT INTO DuplicateFiveMinutes VALUES (103887, 9,4,'Avika', GETDATE()); INSERT INTO DuplicateFiveMinutes VALUES (103887, 10,5,'Panav', GETDATE()); WAITFOR DELAY '00:02:02'; -- |
Rules/Restrictions
The solution should be should use “SELECT” statement or “CTE”.
Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com
Solution – 1 | Using JOINS
-- SELECT m1.MessageID, m2.MessageID, m2.IndividualID , m2.MessageText , m1.DateAdded , m2.DateAdded FROM DuplicateFiveMinutes m1 INNER JOIN DuplicateFiveMinutes m2 ON m2.IndividualID = m1.IndividualID AND m2.MessageText = m1.MessageText WHERE m1.SalesSiteID = 103887 AND m2.MessageID > m1.MessageID AND DATEDIFF(mi,m1.DateAdded,m2.DateAdded) <= 5 /* The time difference should be 5 mins*/ -- |
Output
-- /*------------------------ SELECT m1.MessageID, m2.MessageID, m2.IndividualID , m2.MessageText , m1.DateAdded , m2.DateAdded FROM DuplicateFiveMinutes m1 INNER JOIN DuplicateFiveMinutes m2 ON m2.IndividualID = m1.IndividualID AND m2.MessageText = m1.MessageText WHERE m1.SalesSiteID = 103887 AND m2.MessageID > m1.MessageID AND DATEDIFF(mi,m1.DateAdded,m2.DateAdded) <= 5 /* The time difference should be 5 mins*/ ------------------------*/ MessageID MessageID IndividualID MessageText DateAdded DateAdded -------------------- -------------------- -------------------- --------------------- ----------------------- ----------------------- 1 2 1 Pawan 2017-12-14 12:49:22.373 2017-12-14 12:49:24.373 3 4 2 Sharlee 2017-12-14 12:49:34.377 2017-12-14 12:50:36.377 5 6 3 Ramesh 2017-12-14 12:50:39.380 2017-12-14 12:50:39.380 5 7 3 Ramesh 2017-12-14 12:50:39.380 2017-12-14 12:51:19.380 6 7 3 Ramesh 2017-12-14 12:50:39.380 2017-12-14 12:51:19.380 (5 row(s) affected) -- |
Add a comment if you have any other solution in mind. I would love to learn it. We all need to learn.
Enjoy !!! Keep Learning
Pawan Khowal
Http://MSBISkills.com
select a.MessageID,b.MessageID,a.IndividualId,a.MessageText
from DuplicateFiveMinutes A inner join DuplicateFiveMinutes B on a.SalesSiteID = b.salessiteid
where a.MessageID < b.MessageID
and a.MessageText = b.MessageText
and DATEDIFF(minute,a.DateAdded,b.DateAdded)
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