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SQL Puzzle | The Count Puzzle
The challenge here to write the smallest query. We have to summarized data based on the building Id. Please check the sample input and expected output.
Sample Input
tbl_RealEstate
BldID | RealEstateName |
---|---|
1 | Building 1 |
2 | Building 2 |
3 | Building 3 |
4 | Building 4 |
5 | Building 5 |
6 | Building 6 |
7 | Building 7 |
8 | Building 8 |
9 | Building 9 |
tbl_login
ID | BldID | Name |
---|---|---|
1 | 1 | Name1 |
2 | 1 | Name2 |
3 | 2 | Name3 |
4 | 3 | Name4 |
5 | 2 | Name5 |
6 | 4 | Name6 |
7 | 5 | Name7 |
8 | 6 | Name8 |
9 | 1 | Name9 |
10 | 1 | Name10 |
11 | 2 | Name11 |
12 | 3 | Name12 |
tbl_history
ID | BldID | Username |
---|---|---|
1 | 1 | Name1 |
2 | 1 | Name1 |
3 | 1 | Name9 |
4 | 2 | Name3 |
5 | 3 | Name4 |
6 | 4 | Name6 |
7 | 4 | Name6 |
8 | 4 | Name6 |
9 | 5 | Name7 |
10 | 6 | Name8 |
11 | 8 | Name9 |
12 | 8 | Name10 |
13 | 9 | Name11 |
14 | 9 | Name12 |
Expected Output
BldID | RealEstateName | LoginCount | HistoryCount |
---|---|---|---|
1 | Building 1 | 4 | 3 |
2 | Building 2 | 3 | 1 |
3 | Building 3 | 2 | 1 |
4 | Building 4 | 1 | 3 |
5 | Building 5 | 1 | 1 |
6 | Building 6 | 1 | 1 |
7 | Building 7 | 0 | 0 |
8 | Building 8 | 0 | 2 |
9 | Building 9 | 0 | 2 |
Script
Use below script to create table and insert sample data into it.
-- CREATE TABLE tbl_login ( ID int, BldID int, Name varchar(30) ) GO insert into tbl_login values (1, 1, 'Name1'), (2, 1, 'Name2'), (3, 2, 'Name3'), (4, 3, 'Name4'), (5, 2, 'Name5'), (6, 4, 'Name6'), (7, 5, 'Name7'), (8, 6, 'Name8'), (9, 1, 'Name9'), (10, 1, 'Name10'), (11, 2, 'Name11'), (12, 3, 'Name12'); GO CREATE TABLE tbl_history ( ID int, BldID int, Username varchar(30) ) GO insert into tbl_history values (1, 1, 'Name1'), (2, 1, 'Name1'), (3, 1, 'Name9'), (4, 2, 'Name3'), (5, 3, 'Name4'), (6, 4, 'Name6'), (7, 4, 'Name6'), (8, 4, 'Name6'), (9, 5, 'Name7'), (10, 6, 'Name8'), (11, 8, 'Name9'), (12, 8, 'Name10'), (13, 9, 'Name11'), (14, 9, 'Name12'); GO CREATE TABLE tbl_RealEstate ( BldID int, RealEstateName varchar(30) ) GO insert into tbl_RealEstate values (1, 'Building 1'), (2, 'Building 2'), (3, 'Building 3'), (4, 'Building 4'), (5, 'Building 5'), (6, 'Building 6'), (7, 'Building 7'), (8, 'Building 8'), (9, 'Building 9'); -- |
Rules/Restrictions
The solution should be should use “SELECT” statement or “CTE”.
Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com
Solution – 1
-- SELECT * FROM tbl_RealEstate as r OUTER APPLY ( SELECT COUNT(*) as LoginCount FROM tbl_login as l WHERE BldID = r.BldID )t1 OUTER APPLY ( SELECT COUNT(*) as HistoryCount FROM tbl_history as h WHERE BldID = r.BldID )t2 -- |
Output
-- /*------------------------ SELECT * FROM tbl_RealEstate as r OUTER APPLY ( SELECT COUNT(*) as LoginCount FROM tbl_login as l WHERE BldID = r.BldID )t1 OUTER APPLY ( SELECT COUNT(*) as HistoryCount FROM tbl_history as h WHERE BldID = r.BldID )t2 ------------------------*/ BldID RealEstateName LoginCount HistoryCount ----------- ------------------------------ ----------- ------------ 1 Building 1 4 3 2 Building 2 3 1 3 Building 3 2 1 4 Building 4 1 3 5 Building 5 1 1 6 Building 6 1 1 7 Building 7 0 0 8 Building 8 0 2 9 Building 9 0 2 (9 row(s) affected) --
Add a comment if you have any other solution in mind. I would love to learn it. We all need to learn.
Enjoy !!! Keep Learning
Pawan Khowal
Http://MSBISkills.com
Hi,
My code as follow, but can we write it in single query?
;with cte as (
select t1.RealEstateName,
count(Id) LoginCount
from tbl_RealEstate as t1
left join tbl_login as t2 on t1.BldID=t2.BldID
group by RealEstateName
)
,cte2 as(
select t1.RealEstateName,
count(Id) HistoryCount
from tbl_RealEstate as t1
left join tbl_history as t2 on t1.BldID=t2.BldID
group by RealEstateName
)
select t1.*,
t2.HistoryCount
from cte as t1
inner join cte2 as t2
on t1.RealEstateName=t2.RealEstateName
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