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SQL Puzzle | Get Count and Numbers Puzzle
In this puzzle you have to find total count and their numbers based on the Id values. Please check out the sample input values and sample expected output below.
|122||2017-01-08 00:00:00.000||1 / 1|
|123||2017-01-08 00:00:00.000||1 / 3|
|123||2017-01-10 00:00:00.000||2 / 3|
|123||2017-01-11 00:00:00.000||3 / 3|
Use below script to create table and insert sample data into it.
-- CREATE TABLE Total ( Id INT ,Dates DATETIME ) GO INSERT INTO Total VALUES (123 ,'1/11/2017'), (123 ,'1/10/2017'), (123 ,'1/8/2017'), (122 ,'1/8/2017') GO --
The solution should be should use “SELECT” statement or “CTE”.
Add your solution(s) in the comments section or send you solution(s) to email@example.com
-- SELECT *,CONCAT( ROW_NUMBER() OVER (PARTITION BY Id ORDER BY Dates) , ' / ', COUNT(*) OVER (PARTITION BY Id)) [Count#] FROM Total --
-- SELECT *,CAST( ROW_NUMBER() OVER (PARTITION BY Id ORDER BY Dates) AS VARCHAR(5)) + ' / ' + CAST( COUNT(*) OVER (PARTITION BY Id) AS VARCHAR(5)) [Count#] FROM Total --
Add a comment if you have any other solution in mind. I would love to learn it. We all need to learn.
Enjoy !!! Keep Learning
Abhiram Sharma said:
I love all the posts, I really enjoyed.
I would like more information about this, because it is very nice., Thanks for sharing.
I want to write a query to pull only the first row from the below result set. Having said that the below result set is for 3 unique rows for LocationIds 47,30 and 74 which are valid. Now I want join the 47 i.e location_id on the fly with another table that has LocationId in the join itself to fetch always the latest record location of a customer and display that latest address for each record with same latest address as highlighted below respectively in the second result set.
location_id and last_update_date are available in Location1 table
LocationId is available only in Location2 table
location_id last_update_date Address1 Address2 City LocationId
47 1/9/2014 22:13 118 East #8F NY 47
30 9/18/2013 13:25 405 Taylor St SF 30
71 5/20/2013 16:50 1540 Broadway 17th Floor NY 71
location_id last_update_date Complete (Address1 +Address2) City LocationId
47 1/9/2014 22:13 118 East #8F NY 47
30 9/18/2013 13:25 118 East #8F SF 30
71 5/20/2013 16:50 118 East #8F NY 71
Requirement is to pull the latest address of a Customer based on column last_update_date available only in Location1 table and display the above 3 records with again the latest address 3 times as shown above for each record . That means every time when there are multiple addresses for a customer then I need to display latest address for all the records and I do not want display other available addresses. I will concatenate Address1 and Address2 and display as Complete
Thanks a lot. This was a perfect step-by-step guide. Don’t think it could have been done better.
select *,concat(row_number()over(partition by id order by Dates ),’/’,count(*)over(partition by id))cc from Total
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