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SQL Puzzle | Delete Duplicate Records from a Table but one
In this puzzle you have two tables – a1 and a2. I want to remove duplicates from table a2 which have a entry in a1 table. Please check out the sample input values and sample expected output below.
Table – A1
Table – A2
Expected Output – Table A2
Use below script to create table and insert sample data into it.
-- CREATE TABLE A1 ( ID INT ) GO INSERT INTO A1 VALUES (1),(2) GO CREATE TABLE A2 ( ID INT ) GO INSERT INTO A2 VALUES (1),(2),(1),(3),(3) GO --
The solution should be should use “SELECT” statement or “CTE”.
Add your solution(s) in the comments section or send you solution(s) to firstname.lastname@example.org
-- ;WITH CTE AS ( SELECT *, ROW_NUMBER () OVER (PARTITION BY Id ORDER BY Id) row_num from A2 ) DELETE x FROM a2 x INNER JOIN a1 on a1.Id = x.Id INNER JOIN CTE on x.Id = cte.Id WHERE CTE.row_num <> 1 --
Add a comment if you have any other solution in mind. I would love to learn it. We all need to learn.
Enjoy !!! Keep Learning
select A1.id from A1
select A2.id from A2 where id not in(select * from A1)
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We are looking for some recommendations or best practices for creating or architecture a simple trigger. We have a table that will have data inserted periodically throughout the day. Upon completion of the insert (and possibly updates) we’ll need two things to happen:
1) We’ll update data in a second table. This could be a simple update or possibly calling a stored procedure.
2) We’ll also need to initiate an e-mail
I’ve done some simple triggers before but was not sure of the right structure for combining the two processes. Can I do that in one trigger? Please advise. This is for SQL2014. Look forward to a response.
But nice Article Mate! Great Information! Keep up the good work!
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;with cte as (
select id,ROW_NUMBER()over(partition by id order by (select null))rownum from A2
Delete from cte where id = 1 and rownum = 2
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