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SQL Puzzle | The Longest Period – II
This puzzle is simple. Write a SQL Query to Calculate the longest period ( in days ) that the company has gone without hiring or firing any one.
|1||1000||A||Z||300000.000||2001-09-01 00:00:00.000||2010-01-16 00:00:00.000|
|3||1000||C||X||500000.000||2010-01-15 00:00:00.000||2015-12-02 00:00:00.000|
|5||1000||D||Q||200000.000||2014-04-15 00:00:00.000||2015-12-02 00:00:00.000|
- The challenge is to do it with T-SQL statements only.
- Add your solution(s) in the comments section or send you solution(s) to firstname.lastname@example.org
Script | use below script to create table and insert some sample data
-- CREATE TABLE Employeex ( EmployeeId BIGINT ,DepartmentId INT ,FirstName VARCHAR(1) ,LastName VARCHAR(1) ,Salary NUMERIC(10,3) ,HireDate DATETIME ,TerminationDate DATETIME ) GO INSERT INTO Employeex VALUES (1,1000,'A','Z',300000,'2001-09-01 00:00:00.000','2010-01-16 00:00:00.000'), (2,1000,'B','Y',350000,'2003-03-15 00:00:00.000',NULL), (3,1000,'C','X',500000,'2010-01-15 00:00:00.000','2015-12-02 00:00:00.000'), (4,1000,'D','W',400000,'2012-05-15 00:00:00.000',NULL), (5,1000,'D','Q',200000,'2014-04-15 00:00:00.000','2015-12-02 00:00:00.000'), (6,1000,'E','P',300000,'2015-08-01 00:00:00.000',NULL), (7,1000,'F','N',600000,'2015-12-01 00:00:00.000',NULL), (8,1000,'G','O',700000,'2015-12-01 00:00:00.000',NULL), (9,1000,'H','P',1000000,'2016-01-01 00:00:00.000',NULL) GO --
SOLUTION – 1
-- SELECT MAX(dr) [LongestPeriod] FROM ( SELECT DATEDIFF(d, a, ISNULL(LEAD(a) OVER (ORDER BY a),GETDATE())) dr FROM ( SELECT HireDate a FROM Employeex UNION ALL SELECT TerminationDate FROM Employeex WHERE TerminationDate IS NOT NULL )t )r --
SOLUTION – 2
-- SELECT MAX(gap) [LongestPeriod] FROM ( SELECT DATEDIFF(D, EmpDate, ISNULL(LEAD(EmpDate) OVER (ORDER BY EmpDate),GETDATE())) as gap FROM ( SELECT EmpDate FROM Employeex UNPIVOT(EmpDate FOR DateVal IN (HireDate, TerminationDate)) AS U )TblEmp )TempEmp --
Add a comment if you have a solution in mind. I would love to learn it. We all need to learn.
Enjoy !!! Keep Learning
IF OBJECT_ID(‘tempdb..#temp’) IS NOT NULL
DROP TABLE #temp
create table #temp(row_num int,EmployeeId int ,TerminationDate date)
insert into #temp(row_num,EmployeeId,TerminationDate)
select ROW_NUMBER()over (order by EmployeeId) as row_num ,EmployeeId,TerminationDate from Employeex where TerminationDate is not null
SELECT max(DATEDIFF(DAY, a1.HireDate, a2.HireDate)) as [No.ofdays without hiring] ,null as [No.ofdays without Firing]
from Employeex a1 inner join Employeex a2 on a2.EmployeeId=a1.EmployeeId+1
select null as [No.ofdays without hiring],max(DATEDIFF(DAY, a1.TerminationDate, a2.TerminationDate)) as [No.ofdays without Firing] from #temp a1
inner join #temp a2 on a2.row_num=a1.row_num+1
Pawan Kumar Khowal said:
Sorry it is nor giving proper result.
try with below data..
DELETE FROM employeex
INSERT INTO Employeex VALUES
(1,1000,’A’,’Z’,300000,’2001-09-01 00:00:00.000′,’2010-01-16 00:00:00.000′),
(3,1000,’C’,’X’,500000,’2004-01-15 00:00:00.000′,’2010-12-02 00:00:00.000′),
(5,1000,’D’,’Q’,200000,’2006-04-15 00:00:00.000′,’2008-12-02 00:00:00.000′),
[No.ofdays without hiring] is 560 and
[No.ofdays without Firing] is 320
is it right ?
Pawan Kumar Khowal said:
Number of days without hiring or firing… Answer for the data I have given is 2129.
LikeLiked by 1 person
Soumyendu Paul said:
With Cte as
(Select EmpDate from Employeex
unpivot(EmpDate for Dates in(HireDate,TerminationDate))As upvt),
(Select EmpDate,ROW_NUMBER()over(order by EmpDate)rnk from Cte),
(Select DATEDIFF(D,a.EmpDate,b.EmpDate) [Diff] from Cte1 as a join Cte1 as b
Select Max(Diff) [Max Diff] from Cte_diff
LikeLiked by 1 person
;with cte as (
select Hiredate from Employeex
select Terminationdate from Employeex where Terminationdate is not null
(select Hiredate,DATEDIFF(Day,Lag(Hiredate)over(order by Hiredate),HireDate)daysgap from cte
)select Top 1 daysgap from cte2 order by daysgap desc