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SQL Puzzle | The Date Puzzle – 1
Here you need to write a query that get the number of hours each employee worked on 09/01/2014 between 10am to 1pm.
For details please check out the sample input and the expected output below.
DECLARE @Date AS DATE = ‘2014-09-01′
DECLARE @StartTime AS TIME = ’10:00′
DECLARE @EndTime AS TIME = ’13:00’
|1||2014-09-01 08:00:00.000||2014-09-01 16:45:00.000|
|2||2014-09-01 15:15:00.000||2014-09-02 18:00:00.000|
|3||2014-09-01 11:00:00.000||2014-09-01 18:45:00.000|
|4||2014-09-01 10:00:00.000||2014-09-01 18:45:00.000|
|5||2014-09-01 09:00:00.000||2014-09-01 18:45:00.000|
|6||2014-09-01 10:00:00.000||2014-09-01 18:45:00.000|
|Emp 1 has 3 Hours|
|Emp 2 has 0 Hours|
|Emp 3 has 2 Hours|
|Emp 4 has 3 Hours|
|Emp 5 has 3 Hours|
|Emp 6 has 3 Hours|
- The challenge is to do it with T-SQL statements only.
- Add your solution(s) in the comments section or send you solution(s) to email@example.com
Script | use below script to create table and insert some sample data
-- CREATE TABLE testDt ( EmployeeID INT ,StartDateTime DATETIME ,EndDateTime DATETIME ) GO INSERT INTO testDt VALUES (1 ,'09/01/2014 08:00:00' ,'09/01/2014 16:45:00'), (2 ,'09/01/2014 15:15:00' ,'09/02/2014 18:00:00'), (3 ,'09/01/2014 11:00:00' ,'09/01/2014 18:45:00'), (4 ,'09/01/2014 10:00:00' ,'09/01/2014 18:45:00'), (5 ,'09/01/2014 09:00:00' ,'09/01/2014 18:45:00'), (6 ,'09/01/2014 10:00:00' ,'09/01/2014 18:45:00') GO select * from testDt DECLARE @Date AS DATE = '2014-09-01' DECLARE @StartTime AS TIME = '10:00' DECLARE @EndTime AS TIME = '13:00' --
SOLUTION – 1
Solution will be uploaded tomorrow 🙂
Add a comment if you have a solution in mind. I would love to learn it. We all need to learn.
Enjoy !!! Keep Learning