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SQL Puzzle | Multiplication of Digits Puzzle
Puzzle Statement
In this puzzle you have to find multiplication of digits from an input number/string
Sample Input
Sample Input could be for example – 912 or ‘W912W’
Expected output
Multiplication Of Digits in this case is 18
Rules/Restrictions
The solution should be should use “SELECT” statement or “CTE”.
Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com
Script
SOLUTION # 1 | Using RECURSIVE CTE
-- --Trial # 1st Trial DECLARE @str AS VARCHAR(100) = '912' ;WITH CTE AS ( SELECT 1 start , CASE WHEN SUBSTRING(@str,1,1) LIKE '[0-9]' THEN CAST(SUBSTRING(@str,1,1) AS TINYINT) ELSE 0 END MultiplicationOutput UNION ALL SELECT start + 1 start , MultiplicationOutput * CASE WHEN SUBSTRING(@str,start+1,1) LIKE '[0-9]' THEN CAST(SUBSTRING(@str,start+1,1) AS TINYINT) ELSE 0 END MultiplicationOutput FROM CTE WHERE start < DATALENGTH(@str) ) SELECT MAX(MultiplicationOutput) MultiplicationOutput FROM CTE --#- 2nd Trial DECLARE @str AS VARCHAR(100) = 'W912W' ;WITH CTE AS ( SELECT 1 start , CASE WHEN SUBSTRING(@str,1,1) LIKE '[0-9]' THEN CAST(SUBSTRING(@str,1,1) AS TINYINT) ELSE 1 END MultiplicationOutput UNION ALL SELECT start + 1 start , MultiplicationOutput * CASE WHEN SUBSTRING(@str,start+1,1) LIKE '[0-9]' THEN CAST(SUBSTRING(@str,start+1,1) AS TINYINT) ELSE 0 END MultiplicationOutput FROM CTE WHERE start < DATALENGTH(@str) ) SELECT MAX(MultiplicationOutput) MultiplicationOutput FROM CTE -- |
SOLUTION # 2 | Using Numbers Table & SELECT
-- DECLARE @intValue AS VARCHAR(10) = 265 SELECT EXP(SUM(LOG(CAST(SUBSTRING(@intValue,number,1) AS TINYINT)))) MultiplicationOfDigits FROM ( SELECT DISTINCT number FROM MASTER..SPT_VALUES WHERE number > 0 AND number <= DATALENGTH(@intValue) ) x -- |
Add a comment if you have any other solution in mind. We all need to learn. Enjoy !!!
Keep Learning
Pawan Khowal
Http://MSBISkills.com
DECLARE @t VARCHAR(256) = ‘W912W’;
declare @i INT = 0;
DECLARE @ii INT = 1;
WHILE @i < LEN(@t)
BEGIN
IF ISNUMERIC(SUBSTRING(@t,@i,1)) = 1
SET @ii = cast(SUBSTRING(@t,@i,1) AS INT) * @ii
SET @i = @i + 1;
END
SELECT @ii
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declare @input varchar(10) = ‘1234’;
with cte as
(
select ISNULL(TRY_CAST(SUBSTRING(@input, 1, 1) as int),0) as number, 1 as position
union all
select ISNULL(TRY_CAST(SUBSTRING(@input, position + 1, 1) as int),0) as number, position + 1 as position
from cte
where position < LEN(@input)
)
select EXP(SUM(LOG(number))) from cte
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Hope this solution works :-
;WITH CTE1
AS
(
SELECT @intValue as Val,CAST(IIF(ISNUMERIC(SUBSTRING(@intValue,1,1))=1,SUBSTRING(@intValue,1,1),1) AS bigint) AS MUL,1 AS NUM
UNION ALL
SELECT Val,Mul*IIF(ISNUMERIC(SUBSTRING(Val,NUM+1,1))=1,SUBSTRING(Val,NUM+1,1),1) AS MUL,NUM+1 AS NUM
FROM CTE1
WHERE NUM
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—-Used decimal(32,0) as it is max length for numeric
;WITH CTE
AS
(
SELECT @intValue AS txt
,SUBSTRING(@intValue,1,1) AS sub
,IIF(TRY_CAST(SUBSTRING(@intValue,1,1) AS Decimal(38,0)) is null OR SUBSTRING(@intValue,1,1) =’0′,1,CAST(SUBSTRING(@intValue,1,1) AS Decimal(38,0))) AS nos
,1 AS num
UNION ALL
SELECT txt
,SUBSTRING(txt,NUM+1,1) AS sub
,nos*IIF(TRY_CAST(SUBSTRING(txt,NUM+1,1) AS Decimal(38,0)) is null OR SUBSTRING(txt,NUM+1,1) =’0′,1,SUBSTRING(txt,NUM+1,1)) AS nos
,NUM+1 AS NUM
FROM CTE
WHERE NUM+1
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