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Improving my SQL BI Skills

Improving my SQL BI Skills

Daily Archives: April 11, 2015

T-SQL Query | [ Multiple Ways to Split a String Puzzle ]

11 Saturday Apr 2015

Posted by Pawan Kumar Khowal in SQL SERVER, SQL Server Interview Questions, T SQL Puzzles

≈ 4 Comments

Tags

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T-SQL Query | [ Multiple Ways to Split a String Puzzle ]

Puzzle Statement

  1. The puzzle is very simple. We have an input table TestMultipleColumns with two columns ID, Name.
  2. We have to split the column via comma – Name into two columns named Name and Surname.
  3. E.g. Pawan,Kumar would be Pawan in the name column and Kumar in the Surname column
  4. Please check out the sample input and expected output for details.

Sample Input

Id Name
1 Pawan,Kumar
2 Sandeep,Goyal
3 Isha,Mattoo
4 Gopal,Ranjan
5 Neeraj,Garg
6 Deepak,Sharma
7 Mayank,Tripathi

 Expected output

Id Name Surname
1 Pawan Kumar
2 Sandeep Goyal
3 Isha Mattoo
4 Gopal Ranjan
5 Neeraj Garg
6 Deepak Sharma
7 Mayank Tripathi

Rules/Restrictions

  • The solution should be should use “SELECT” statement or “CTE”.
  • Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com

Script

Use the below script to generate the source table and fill them up with the sample data.

--

CREATE TABLE [dbo].[TestMultipleColumns]

(

[Id] [int] NULL,

[Name] [varchar](20) NULL

)

INSERT INTO [TestMultipleColumns] VALUES

(1,    'Pawan,Kumar'),

(2,    'Sandeep,Goyal'),

(3,    'Isha,Mattoo'),

(4,    'Gopal,Ranjan'),

(5,    'Neeraj,Garg'),

(6,    'Deepak,Sharma'),

(7,    ' Mayank,Tripathi')

GO

--

UPDATE – 11-Apr-2015 – Solution 1,2 & 3


--

--SOLUTION 1 - Using PARSENAME
SELECT Id,
       PARSENAME(REPLACE(Name,',','.'),2) Name,
       PARSENAME(REPLACE(Name,',','.'),1) Surname
FROM TestMultipleColumns

--SOLUTION 2 - USING SUBSTRING & CHARINDEX
SELECT Id,
       SUBSTRING(Name,1,CHARINDEX(',',Name)-1) Name,
       SUBSTRING(Name,CHARINDEX(',',Name)+1,LEN(Name)) Surname
 FROM TestMultipleColumns 

--SOLUTION 3 - Using XML method
;With CTE
AS
(
    SELECT Id, Name,
    CAST(('<r><n>' + REPLACE(Name,',', '</n><n>') + '</n></r>') AS XML) X
   FROM TestMultipleColumns
)
SELECT  Id,
 i.value('n[1]','VARCHAR(50)') AS Name,
 i.value('n[2]','VARCHAR(50)') AS Surname
FROM CTE c
CROSS APPLY c.X.nodes('/r') x(i)

--SOLUTION 4
--For comma seperated string


DECLARE @x AS XML=''
DECLARE @Param AS VARCHAR(100) = 'Ind,Hary,Gu'
SET @x = CAST('<A>'+ REPLACE(@Param,',','</A><A>')+ '</A>' AS XML)
SELECT t.value('.', 'VARCHAR(10)') Value FROM @x.nodes('/A') AS x(t)

--

Add a comment if you have any other solution in mind. We all need to learn.

Keep Learning

Http://MSBISkills.com

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T-SQL Query | [How Many Work/Week Days In Date Range Puzzle]

11 Saturday Apr 2015

Posted by Pawan Kumar Khowal in SQL SERVER, SQL Server Interview Questions, T SQL Puzzles

≈ Leave a comment

Tags

Complex SQL Challenges, Complex TSQL Challenge, Interview Qs.SQL SERVER Questions, Interview questions on Joins, Interview Questions on SQL, InterviewQuestions, InterviewQuestions for SQL, Joins, Joins Interview questions, Joins Puzzle, Learn complex SQL, Learn SQL, Learn T-SQL, Objective Puzzle, PL/SQL Challenges, Puzzles, Queries for SQL Interview, SELECT Puzzle, SQL, SQL 2012, SQL 2014, SQL 2014 Interview Questions, SQL Challenge, SQL Challenges, SQL Joins, SQL pl/sql puzzles, SQL Puzzles, SQL Queries, SQL SERVER Interview questions, SQL SERVER Puzzles, SQL Skills, SQL Sudoku, SQLSERVER, T SQL Puzzles, T-SQL Challenge, Tough SQL Challenges, Tough SQL Puzzles, TSQL, TSQL Challenge, TSQL Challenges, TSQL Interview questions, TSQL Queries


T-SQL Query | [How Many Work/Week Days In Date Range Puzzle]

The puzzle is very simple. You have to calculate how many week days existed in an arbitrary range of dates today. We have count no of days between the dates but Saturday’s and Sunday’s. Please check out the sample input and expected output for details.

Sample Input

For example date range is-

Start Date – ’10/1/2008′
End Date – ’10/31/2008′

Expected output

WeekDaysinGivenPeriod
23

Rules/Restrictions
• The solution should be should use “SELECT” statement or “CTE”.
• Do not use Loop.
• Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com

UPDATE – 11-Apr-2015 – Solution 1


DECLARE @st AS DATETIME = '10/1/2008'
DECLARE @Et AS DATETIME = '10/31/2008'

;WITH CTE AS
(
     SELECT @st Dts , DATEPART(weekday,@st) wk
     UNION ALL
     SELECT DATEADD(d,1,Dts) ,  DATEPART(weekday, DATEADD(d,1,Dts)) wk  FROM CTE
     WHERE DATEADD(d,1,Dts) <= @Et
)
SELECT COUNT(1) WeekDaysinGivenPeriod FROM CTE WHERE wk <> 1 AND wk <> 7

--

Add a comment if you have any other solution in mind. We all need to learn.

Keep Learning

http://MSBISkills.com

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