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Improving my SQL BI Skills

Improving my SQL BI Skills

Daily Archives: March 24, 2015

T-SQL Query | [ Consecutive Wins for India Puzzle ]

24 Tuesday Mar 2015

Posted by Pawan Kumar Khowal in SQL SERVER, T SQL Puzzles

≈ 4 Comments

Tags

Complex SQL Challenges, Complex TSQL Challenge, Interview Qs.SQL SERVER Questions, Interview Questions on SQL, InterviewQuestions, InterviewQuestions for SQL, Learn complex SQL, Learn SQL, Learn T-SQL, PL/SQL Challenges, Puzzles, Queries for SQL Interview, SQL, SQL 2012, SQL 2014, SQL 2014 Interview Questions, SQL Challenge, SQL Challenges, SQL pl/sql puzzles, SQL Puzzles, SQL SERVER Interview questions, SQL SERVER2005/2008, SQL Sudoku, SQLSERVER, T SQL Puzzles, T-SQL Challenge, Tough SQL Challenges, Tough SQL Puzzles, TSQL, TSQL Challenge, TSQL Challenges, TSQL Interview questions, TSQL Queries


T-SQL Query | [ Consecutive Wins for India Puzzle ]  – In this puzzle we have to find the maximum consecutive wins for India in India Vs Australia series. Please check out the sample input and expected output for details.

Sample Input

TeamA TeamB MatchDate WinsBy
Ind Aus 10-01-2014 Ind
Ind Aus 15-01-2014 Ind
Ind Aus 19-01-2014 Ind
Ind Aus 23-01-2014 Aus
Ind Aus 27-01-2014 Ind
Ind Aus 31-01-2014 Ind

Expected Output

TeamA TeamB MatchDate WinsBy
Ind Aus 10-01-2014 Ind
Ind Aus 15-01-2014 Ind
Ind Aus 19-01-2014 Ind

Rules/Restrictions

  • The solution should be should use “SELECT” statement or “CTE”.
  • Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com

Script

Use the below script to generate the source table and fill them up with the sample data.


--Create table

CREATE TABLE IndAusSeries
(
TeamA VARCHAR(3)
,TeamB VARCHAR(3)
,MatchDate DATETIME
,WinsBy VARCHAR(3)
)
GO

--Insert Data

INSERT INTO IndAusSeries(TeamA,TeamB,MatchDate,WinsBy)
VALUES
('Ind','Aus','01-10-2014','Ind'),
('Ind','Aus','01-15-2014','Ind'),
('Ind','Aus','01-19-2014','Ind'),
('Ind','Aus','01-23-2014','Aus'),
('Ind','Aus','01-27-2014','Ind'),
('Ind','Aus','01-31-2014','Ind')

--Verify Data

SELECT TeamA,TeamB,MatchDate,WinsBy FROM IndAusSeries

Update Apr 28 | Solution 1


--

-----------Method 1 | Pawan Kumar Khowal ----------------


;WITH CTE1 AS
(
    SELECT * , ROW_NUMBER() OVER  (ORDER BY %%Physloc%%) rnk 
	FROM IndAusSeries
)
,CTE2 AS
(
	SELECT *, 
		CASE WHEN WinsBy = lag(WinsBy) 
		over(order by rnk) THEN 0 ELSE 1 END cols 
	FROM CTE1 c2		 
)
,CTE3 AS
(
	SELECT * , SUM(cols) OVER (ORDER BY rnk) grouper FROM CTE2
)
,CTE4 AS
(
	SELECT grouper,COUNT(grouper) Maxy FROM CTE3 GROUP BY grouper
)
,CTE5 AS
(
	SELECT MAX(Maxy) Maxy FROM CTE4
)
SELECT c.TeamA , c.TeamB , c.MatchDate , c.WinsBy 
FROM CTE4 a 
INNER JOIN CTE5 b ON a.Maxy = b.Maxy 
INNER JOIN CTE3 c ON c.grouper = a.grouper

--

Update Apr 28 | Solution 2


--

-----------Method 2 | Deepak Sharma ----------------


WITH CTE 
AS 
(
	SELECT * 
		, RANK() OVER (PARTITION BY a.WinsBy,a.lag ORDER BY a.MatchDate) rnk
		, ROW_NUMBER() OVER (ORDER BY MatchDate) rnum 
	FROM 
	(
		SELECT *, 
			REPLACE(lag(winsby,1,0) OVER (ORDER BY MatchDate),'0','Ind') lag 
		FROM IndAusSeries
	) a
)
SELECT TeamA,TeamB,MatchDate,WinsBy from CTE where rnk = rnum


--

Update Apr 28 | Solution 3


--

-----------Method 3 | Isha Mattoo ----------------


;WITH CTE AS 
(
	SELECT TeamA,TeamB,MatchDate,WinsBy
        
,ISNULL(Lead(WinsBy) OVER (ORDER BY (SELECT NULL)),0) AS NextWin
	FROM IndAusSeries
)
,CTE2 AS 
(
	SELECT *,IIF(NextWin<> WinsBy,1,0) AS a
        ,ROW_NUMBER() OVER( ORDER BY (SELECT NULL)) AS b
	from cte
)
,CTE3 AS 
(
	SELECT *, b - ISNULL(lag(b) OVER (ORDER BY (SELECT NULL)),0) AS C FROM CTE2
	WHERE a = 1
)
SELECT t2.* FROM cte3 t1
RIGHT OUTER JOIN IndAusSeries t2 ON t1.MatchDate = t2.MatchDate
WHERE t2.MatchDate  <= (SELECT MatchDate FROM cte3 WHERE C = (SELECT MAX(C) FROM CTE3))
AND t2.WinsBy = (SELECT WinsBy FROM cte3 WHERE C = (SELECT MAX(C) FROM CTE3))


--

Add a comment if you have any other solution in mind. We all need to learn.

Keep Learning

http://MSBISkills.com

T-SQL Query | [ Year and Month wise data – The Pivot Puzzle ]

24 Tuesday Mar 2015

Posted by Pawan Kumar Khowal in SQL SERVER, T SQL Puzzles

≈ 2 Comments

Tags

Complex SQL Challenges, Complex TSQL Challenge, Interview Qs.SQL SERVER Questions, Interview Questions on SQL, InterviewQuestions, InterviewQuestions for SQL, Learn complex SQL, Learn SQL, Learn T-SQL, PL/SQL Challenges, Puzzles, Queries for SQL Interview, SQL, SQL 2012, SQL 2014, SQL 2014 Interview Questions, SQL Challenge, SQL Challenges, SQL pl/sql puzzles, SQL Puzzles, SQL SERVER Interview questions, SQL SERVER2005/2008, SQL Sudoku, SQLSERVER, T SQL Puzzles, T-SQL Challenge, Tough SQL Challenges, Tough SQL Puzzles, TSQL, TSQL Challenge, TSQL Challenges, TSQL Interview questions, TSQL Queries


T-SQL Query | [ Year & Month wise data – The Pivot Puzzle ]  – In this puzzle we have to transpose the data to show year and month wise data. Please check out the sample input and expected output for details.

Sample Input

Year1 Month1 Amount
2014 Jan 1000
2014 Feb 1200
2014 Mar 1300
2013 Jan 3000

 

Expected Output

 

Year1 Jan Feb Mar
2013 3000 NULL NULL
2014 1000 1200 1300

Rules/Restrictions

  • The solution should be should use “SELECT” statement or “CTE”.
  • Add your solution(s) in the comments section or send you solution(s) to pawankkmr@gmail.com

Script

Use the below script to generate the source table and fill them up with the sample data.


--Create table

CREATE TABLE TestTranspose
(
 Year1 INT
,Month1 VARCHAR(3)
,Amount INT
)
GO

--Insert Data

INSERT INTO TestTranspose Values (2014,'Jan',1000),(2014,'Feb',1200),(2014,'Mar',1300)
INSERT INTO TestTranspose Values (2013,'Jan',3000)

--Verify Data

SELECT Year1,Month1,Amount FROM TestTranspose

UPDATE – 21-Apr-2015 – Solution 1


--


--Solution 1



;WITH CTE AS 
(
       SELECT 1 rnk , 'Jan' Mm
       UNION ALL
       SELECT 2 , 'Feb'
       UNION ALL
       SELECT 3 , 'Mar'
)
,CTE3 AS
(
       SELECT T.* , rnk 
       FROM TestTranspose T INNER JOIN CTE c ON C.Mm = T.Month1
)
,CTE4 AS
(
       SELECT Year1,[1] Jan ,[2] Feb ,[3] Mar FROM CTE3
       PIVOT 
       (SUM(Amount) FOR rnk IN ([1],[2],[3])) p
) 
SELECT Year1 , SUM(Jan) Jan , SUM(Feb) Feb , SUM(Mar) Mar FROM CTE4 GROUP  BY Year1


--

Add a comment if you have any other solution in mind. We all need to learn.

Keep Learning

http://MSBISkills.com

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Pawan Khowal

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